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أوجد المشتق العكسي لـ
∫2xx2+2dx\int_{ }^{ }\frac{2x}{x^2+2}dx∫x2+22xdx
ln∣x2+2∣+1x+c\ln\left|x^2+2\right|+\frac{1}{x}+cln∣∣x2+2∣∣+x1+c
ln∣x2+2∣+c\ln\left|x^2+2\right|+cln∣∣x2+2∣∣+c
ln∣x+1x∣+c\ln\left|\frac{x^{ }+1}{x}\right|+cln∣∣xx+1∣∣+c
أكمل هذا البيان
إذا كان
f (x)=2Cos x و g(x)=ex
إذن ∫[f(x) - g(x)] dx = ___________.
x22+ex+c\frac{x^2}{2}+e^x+c2x2+ex+c
2sinx−ex+c2\sin x-e^x+c2sinx−ex+c
2ex+x+c2e^x+x+c2ex+x+c
إذا كان f (x)=ex و g(x)=x3
إذن
∫[f(x) - g(x)] dx =___________.
x22+ex+c\frac{x^2}{2}+e^x+c2x2+ex+c
ex−14x4+ce^x-\frac{1}{4}x^4+cex−41x4+c
ex+14x4+ce^x+\frac{1}{4}x^4+cex+41x4+c
f (x)=Sinx و g(x)=loglogx
∫[f(x) -g(x)] dx = ___________.
2x2cosx−xloglogx+c2x^2\cos x-x\log\log x+c2x2cosx−xloglogx+c
−cosx+xloglogx−x+c-\cos x+x\log\log x-x+c−cosx+xloglogx−x+c
−cosx−xloglogx+x+c-\cos x-x\log\log x+x+c−cosx−xloglogx+x+c
∫11+sinxdx\int_{ }^{ }\frac{1}{1+\sin x}dx∫1+sinx1dx
sinx−tanx+c\sin x-\tan x+csinx−tanx+c
−secx+tanx+c-\sec x+\tan x+c−secx+tanx+c
secx−tanx+c\sec x-\tan x+csecx−tanx+c
∫(sinx−1)cos2xdx\int_{ }^{ }\frac{\left(\sin x-1\right)}{\cos^2x}dx∫cos2x(sinx−1)dx
secx+tanx+c\sec x+\tan x+csecx+tanx+c
f (x)=3x و g(x)=ex
فإن ∫[f(x) - g(x)] dx = ___________.
3x22−ex+c\frac{3x^2}{2}-e^x+c23x2−ex+c
x+ex+cx+e^x+cx+ex+c
ex−x+ce^x-x+cex−x+c
∫1x2+4x+8dx\int_{ }^{ }\frac{1}{x^2+4x+8}dx∫x2+4x+81dx
12 x+24\frac{1}{2}\ \frac{x+2}{4}21 4x+2
ln∣x+1∣+1x+1+c\ln\left|x+1\right|+\frac{1}{x+1}+cln∣x+1∣+x+11+c
12 x+22+c\frac{1}{2}\ \frac{x+2}{2}+c21 2x+2+c
∫xx2+2x+1dx\int_{ }^{ }\frac{x}{x^2+2x+1}dx∫x2+2x+1xdx
ln∣x+1∣+c\ln\left|x+1\right|+cln∣x+1∣+c
−19x9+c-\frac{1}{9x^9}+c−9x91+c
قيّم التكامل
∫2x+3x2−9dx\int_{ }^{ }\frac{2x+3}{x^2-9}dx∫x2−92x+3dx
ln∣x2∣−2x+2ln∣x+1∣+c\ln\left|x^2\right|-2x+2\ln\left|x+1\right|+cln∣∣x2∣∣−2x+2ln∣x+1∣+c
12ln∣(x−3)2(x+3)∣+c\frac{1}{2}\ln\left|\left(x-3\right)^2\left(x+3\right)\right|+c21ln∣∣(x−3)2(x+3)∣∣+c
x2−2x+2ln∣x+1∣+cx^2-2x+2\ln\left|x+1\right|+cx2−2x+2ln∣x+1∣+c
إنتهى الإختبار.