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Identify rational function from the graph:
f(x)=xx+1f\left(x\right)=\frac{x}{x+1}f(x)=x+1x
f(x)=2xx2 − 1f\left(x\right)=\frac{2x}{x^2\ -\ 1}f(x)=x2 − 12x
f(x)=1x2+1f(x)=\frac{1}{x^2+1}f(x)=x2+11
f(x)=1x2−1f(x)=\frac{1}{x^2-1}f(x)=x2−11
f(x)=2x(x2−1)f\left(x\right)=\frac{2x}{\left(x^2-1\right)}f(x)=(x2−1)2x
f(x)=2xx2+1f\left(x\right)=\frac{2x}{x^2+1}f(x)=x2+12x
identify rational function from the graph:
f(x)=−xx3+3f\left(x\right)=\frac{-x}{x^3+3}f(x)=x3+3−x
f(x)=xx+3f(x)=\frac{x}{x+3}f(x)=x+3x
f(x)=1x2−1f\left(x\right)=\frac{1}{x^2-1}f(x)=x2−11
f(x)=2x(x2+1)f\left(x\right)=\frac{2x}{\left(x^2+1\right)}f(x)=(x2+1)2x
f(x)=−xx−3f\left(x\right)=\frac{-x}{x-3}f(x)=x−3−x
f(x)=5xx+3f(x)=\frac{5x}{x+3}f(x)=x+35x
f(x)=2x(x2+1)f(x)=\frac{2x}{\left(x^2+1\right)}f(x)=(x2+1)2x
It is done.
