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Evaluate f(2) in f(x)=2x.f(2)\ in\ f(x)=\frac{2}{x}.f(2) in f(x)=x2.
Evaluate f(x)=x2−3xf\left(x\right)=\frac{x^2-3}{x}f(x)=xx2−3 for x=5x=5x=5
225\frac{22}{5}522
125\frac{12}{5}512
205\frac{20}{5}520
Evaluate f(x)=2x−3f\left(x\right)=\frac{2}{x-3}f(x)=x−32 for x=−3x=-3x=−3
2−6\frac{2}{-6}−62
7−2\frac{7}{-2}−27
2−3\frac{2}{-3}−32
Evaluate f(x)=2x+3f\left(x\right)=\frac{2}{x+3}f(x)=x+32 for x=2x=2x=2
23\frac{2}{3}32
25\frac{2}{5}52
24\frac{2}{4}42
Evaluate f(x)=x+5x−2f\left(x\right)=\frac{x+5}{x-2}f(x)=x−2x+5 for x=2x=2x=2 .
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4
Evaluate f(−1) in f(x)=x2+1x.f(-1)\ in\ f(x)=\frac{x^2+1}{x}.f(−1) in f(x)=xx2+1.
Evaluate f(x)=x+22x+5f\left(x\right)=\frac{x+2}{2x+5}f(x)=2x+5x+2 for x=1x=1x=1
27\frac{2}{7}72
37\frac{3}{7}73
evaluate f(x)=x2−3x−1f\left(x\right)=\frac{x^2-3}{x-1}f(x)=x−1x2−3 for x=3x=3x=3
3
5
0
Evaluate f(0) in f(x)=2x+12x−1.f(0)\ in\ f(x)=\frac{2x+1}{2x-1}.f(0) in f(x)=2x−12x+1.
Evaluate f(4) in f(x)=x+1x−1.f(4)\ in\ f(x)=\frac{x+1}{x-1}.f(4) in f(x)=x−1x+1.
It is done.